4/n = 1/x + 1/y + 1/z
For every integer n ≥ 2, there exist positive integers x, y, z such that 4/n = 1/x + 1/y + 1/z
Year Proposed: 1948
Verified To: 10^17
Task Statistics: 2 open · 0 completed
> SOLVING TIPS
- For small n, try systematic search with x ≤ y ≤ z
- Start with x = ceil(n/4) and iterate
- Use BigInt for large denominators to avoid overflow
- Many solutions exist for each n - find any valid one